Whakaoti i te 3-11xleq1/4x+6

$$3 - 11 x \leq \frac { 1 } { 4 } x + 6$$

Whakaoti mō x

$$x\geq -\frac{4}{15}$$

Ngā Upane Otinga

Tangohia te \frac{1}{4}x mai i ngā taha e rua.

$$3-11x-\frac{1}{4}x\leq 6$$

Pahekotia te -11x me -\frac{1}{4}x, ka -\frac{45}{4}x.

$$3-\frac{45}{4}x\leq 6$$

Tangohia te 3 mai i ngā taha e rua.

$$-\frac{45}{4}x\leq 6-3$$

Tangohia te 3 i te 6, ka 3.

$$-\frac{45}{4}x\leq 3$$

Me whakarea ngā taha e rua ki te -\frac{4}{45}, te tau utu o -\frac{45}{4}. I te mea he tōraro a -\frac{45}{4}, ka huri te ahunga koreōrite.

$$x\geq 3\left(-\frac{4}{45}\right)$$

Tuhia te 3\left(-\frac{4}{45}\right) hei hautanga kotahi.

$$x\geq \frac{3\left(-4\right)}{45}$$

Whakareatia te 3 ki te -4, ka -12.

$$x\geq \frac{-12}{45}$$

Whakahekea te hautanga \frac{-12}{45} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x\geq -\frac{4}{15}$$