Whakaoti i te 3-2*(z-1)/6=8z+1/3

$$3 - \frac { 2 \cdot ( z - 1 ) } { 6 } = \frac { 8 z + 1 } { 3 }$$

Whakaoti mō z

$$z=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me whakarea ngā taha e rua o te whārite ki te 6, arā, te tauraro pātahi he tino iti rawa te kitea o 6,3.

$$18-2\left(z-1\right)=2\left(8z+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te z-1.

$$18-2z+2=2\left(8z+1\right)$$

Tāpirihia te 18 ki te 2, ka 20.

$$20-2z=2\left(8z+1\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 8z+1.

$$20-2z=16z+2$$

Tangohia te 16z mai i ngā taha e rua.

$$20-2z-16z=2$$

Pahekotia te -2z me -16z, ka -18z.

$$20-18z=2$$

Tangohia te 20 mai i ngā taha e rua.

$$-18z=2-20$$

Tangohia te 20 i te 2, ka -18.

$$-18z=-18$$

Whakawehea ngā taha e rua ki te -18.

$$z=\frac{-18}{-18}$$

Whakawehea te -18 ki te -18, kia riro ko 1.

$$z=1$$