Whakaoti i te 3(x-4)^2=-6

$$3 ( x - 4 ) ^ { 2 } = - 6$$

Whakaoti mō x (complex solution)

$$x=-\sqrt{2}i+4\approx 4-1.414213562i$$

$$x=4+\sqrt{2}i\approx 4+1.414213562i$$

Ngā Upane mā te Kimi Pūtakerua

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$\left(x-4\right)^{2}=-\frac{6}{3}$$

Whakawehe -6 ki te 3.

$$\left(x-4\right)^{2}=-2$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x-4=\sqrt{2}i x-4=-\sqrt{2}i$$

Me tāpiri 4 ki ngā taha e rua o te whārite.

$$x-4-\left(-4\right)=\sqrt{2}i-\left(-4\right) x-4-\left(-4\right)=-\sqrt{2}i-\left(-4\right)$$

Mā te tango i te -4 i a ia ake anō ka toe ko te 0.

$$x=\sqrt{2}i-\left(-4\right) x=-\sqrt{2}i-\left(-4\right)$$

Tango -4 mai i i\sqrt{2}.

$$x=4+\sqrt{2}i$$

Tango -4 mai i -i\sqrt{2}.

$$x=-\sqrt{2}i+4$$

Kua oti te whārite te whakatau.

$$x=4+\sqrt{2}i x=-\sqrt{2}i+4$$