Whakaoti i te 3(x+2)-10=1/4(12x-16)

$$3 ( x + 2 ) - 10 = \frac { 1 } { 4 } ( 12 x - 16 )$$

Whakaoti mō x (complex solution)

$$x\in \mathrm{C}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te x+2.

$$3x+6-10=\frac{1}{4}\left(12x-16\right)$$

Tangohia te 10 i te 6, ka -4.

$$3x-4=\frac{1}{4}\left(12x-16\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{4} ki te 12x-16.

$$3x-4=\frac{1}{4}\times 12x+\frac{1}{4}\left(-16\right)$$

Whakareatia te \frac{1}{4} ki te 12, ka \frac{12}{4}.

$$3x-4=\frac{12}{4}x+\frac{1}{4}\left(-16\right)$$

Whakawehea te 12 ki te 4, kia riro ko 3.

$$3x-4=3x+\frac{1}{4}\left(-16\right)$$

Whakareatia te \frac{1}{4} ki te -16, ka \frac{-16}{4}.

$$3x-4=3x+\frac{-16}{4}$$

Whakawehea te -16 ki te 4, kia riro ko -4.

$$3x-4=3x-4$$

Tangohia te 3x mai i ngā taha e rua.

$$3x-4-3x=-4$$

Pahekotia te 3x me -3x, ka 0.

$$-4=-4$$

Whakatauritea te -4 me te -4.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{C}$$

Whakaoti mō x

$$x\in \mathrm{R}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te x+2.

$$3x+6-10=\frac{1}{4}\left(12x-16\right)$$

Tangohia te 10 i te 6, ka -4.

$$3x-4=\frac{1}{4}\left(12x-16\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{4} ki te 12x-16.

$$3x-4=\frac{1}{4}\times 12x+\frac{1}{4}\left(-16\right)$$

Whakareatia te \frac{1}{4} ki te 12, ka \frac{12}{4}.

$$3x-4=\frac{12}{4}x+\frac{1}{4}\left(-16\right)$$

Whakawehea te 12 ki te 4, kia riro ko 3.

$$3x-4=3x+\frac{1}{4}\left(-16\right)$$

Whakareatia te \frac{1}{4} ki te -16, ka \frac{-16}{4}.

$$3x-4=3x+\frac{-16}{4}$$

Whakawehea te -16 ki te 4, kia riro ko -4.

$$3x-4=3x-4$$

Tangohia te 3x mai i ngā taha e rua.

$$3x-4-3x=-4$$

Pahekotia te 3x me -3x, ka 0.

$$-4=-4$$

Whakatauritea te -4 me te -4.

$$\text{true}$$

He pono tēnei mō tētahi x ahakoa.

$$x\in \mathrm{R}$$