Whakaoti i te 3(a+b-2)=1/3(4a+3)

$$3 ( a + b - 2 ) = \frac { 1 } { 3 } ( 4 a + 3 )$$

Whakaoti mō a

$$a=\frac{21-9b}{5}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te a+b-2.

$$3a+3b-6=\frac{1}{3}\left(4a+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te 4a+3.

$$3a+3b-6=\frac{4}{3}a+1$$

Tangohia te \frac{4}{3}a mai i ngā taha e rua.

$$3a+3b-6-\frac{4}{3}a=1$$

Pahekotia te 3a me -\frac{4}{3}a, ka \frac{5}{3}a.

$$\frac{5}{3}a+3b-6=1$$

Tangohia te 3b mai i ngā taha e rua.

$$\frac{5}{3}a-6=1-3b$$

Me tāpiri te 6 ki ngā taha e rua.

$$\frac{5}{3}a=1-3b+6$$

Tāpirihia te 1 ki te 6, ka 7.

$$\frac{5}{3}a=7-3b$$

Whakawehea ngā taha e rua o te whārite ki te \frac{5}{3}, he ōrite ki te whakarea i ngā taha e rua ki te tau huripoki o te hautanga.

$$\frac{\frac{5}{3}a}{\frac{5}{3}}=\frac{7-3b}{\frac{5}{3}}$$

Mā te whakawehe ki te \frac{5}{3} ka wetekia te whakareanga ki te \frac{5}{3}.

$$a=\frac{7-3b}{\frac{5}{3}}$$

Whakawehe 7-3b ki te \frac{5}{3} mā te whakarea 7-3b ki te tau huripoki o \frac{5}{3}.

$$a=\frac{21-9b}{5}$$

Whakaoti mō b

$$b=-\frac{5a}{9}+\frac{7}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te a+b-2.

$$3a+3b-6=\frac{1}{3}\left(4a+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te 4a+3.

$$3a+3b-6=\frac{4}{3}a+1$$

Tangohia te 3a mai i ngā taha e rua.

$$3b-6=\frac{4}{3}a+1-3a$$

Pahekotia te \frac{4}{3}a me -3a, ka -\frac{5}{3}a.

$$3b-6=-\frac{5}{3}a+1$$

Me tāpiri te 6 ki ngā taha e rua.

$$3b=-\frac{5}{3}a+1+6$$

Tāpirihia te 1 ki te 6, ka 7.

$$3b=-\frac{5}{3}a+7$$

He hanga arowhānui tō te whārite.

$$3b=-\frac{5a}{3}+7$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3b}{3}=\frac{-\frac{5a}{3}+7}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$b=\frac{-\frac{5a}{3}+7}{3}$$

Whakawehe -\frac{5a}{3}+7 ki te 3.

$$b=-\frac{5a}{9}+\frac{7}{3}$$