Whakaoti mō x
x=\frac{\log_{5}\left(12\right)-1}{3}\approx 0.18131977
Whakaoti mō x (complex solution)
x=\frac{2\pi n_{1}i}{3\ln(5)}+\frac{\log_{5}\left(12\right)}{3}-\frac{1}{3}
n_{1}\in \mathrm{Z}
Graph
Tohaina
Kua tāruatia ki te papatopenga
3\times 5^{3x+1}=36
Whakamahia ngā ture taupū me ngā taupū kōaro hei whakaoti i te whārite.
5^{3x+1}=12
Whakawehea ngā taha e rua ki te 3.
\log(5^{3x+1})=\log(12)
Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.
\left(3x+1\right)\log(5)=\log(12)
Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.
3x+1=\frac{\log(12)}{\log(5)}
Whakawehea ngā taha e rua ki te \log(5).
3x+1=\log_{5}\left(12\right)
Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
3x=\log_{5}\left(12\right)-1
Me tango 1 mai i ngā taha e rua o te whārite.
x=\frac{\log_{5}\left(12\right)-1}{3}
Whakawehea ngā taha e rua ki te 3.
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