Whakaoti i te 3(2x-3(x+1))+8=4x-(x+3)

$$3 ( 2 x - 3 ( x + 1 ) ) + 8 = 4 x - ( x + 3 )$$

Whakaoti mō x

$$x=\frac{1}{3}\approx 0.333333333$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te x+1.

$$3\left(2x-3x-3\right)+8=4x-\left(x+3\right)$$

Pahekotia te 2x me -3x, ka -x.

$$3\left(-x-3\right)+8=4x-\left(x+3\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te -x-3.

$$-3x-9+8=4x-\left(x+3\right)$$

Tāpirihia te -9 ki te 8, ka -1.

$$-3x-1=4x-\left(x+3\right)$$

Hei kimi i te tauaro o x+3, kimihia te tauaro o ia taurangi.

$$-3x-1=4x-x-3$$

Pahekotia te 4x me -x, ka 3x.

$$-3x-1=3x-3$$

Tangohia te 3x mai i ngā taha e rua.

$$-3x-1-3x=-3$$

Pahekotia te -3x me -3x, ka -6x.

$$-6x-1=-3$$

Me tāpiri te 1 ki ngā taha e rua.

$$-6x=-3+1$$

Tāpirihia te -3 ki te 1, ka -2.

$$-6x=-2$$

Whakawehea ngā taha e rua ki te -6.

$$x=\frac{-2}{-6}$$

Whakahekea te hautanga \frac{-2}{-6} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -2.

$$x=\frac{1}{3}$$