Whakaoti i te 3x^2+12x

$$3 { x }^{ 2 } +12x$$

Tauwehe

$$3x\left(x+4\right)$$

Ngā Upane Otinga

Tauwehea te 3.

$$3\left(x^{2}+4x\right)$$

Whakaarohia te x^{2}+4x. Tauwehea te x.

$$x\left(x+4\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$3x\left(x+4\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$3x^{2}+12x=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-12±\sqrt{12^{2}}}{2\times 3}$$

Tuhia te pūtakerua o te 12^{2}.

$$x=\frac{-12±12}{2\times 3}$$

Whakareatia 2 ki te 3.

$$x=\frac{-12±12}{6}$$

Nā, me whakaoti te whārite x=\frac{-12±12}{6} ina he tāpiri te ±. Tāpiri -12 ki te 12.

$$x=\frac{0}{6}$$

Whakawehe 0 ki te 6.

$$x=0$$

Nā, me whakaoti te whārite x=\frac{-12±12}{6} ina he tango te ±. Tango 12 mai i -12.

$$x=-\frac{24}{6}$$

Whakawehe -24 ki te 6.

$$x=-4$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 0 mō te x_{1} me te -4 mō te x_{2}.

$$3x^{2}+12x=3x\left(x-\left(-4\right)\right)$$

Whakamāmātia ngā kīanga katoa o te āhua p-\left(-q\right) ki te p+q.

$$3x^{2}+12x=3x\left(x+4\right)$$

Aromātai

$$3x\left(x+4\right)$$