Whakaoti i te 3*(x-1)-(-x+1)=2*(x+2)

$$3 \cdot ( x - 1 ) - ( - x + 1 ) = 2 \cdot ( x + 2 )$$

Whakaoti mō x

$$x=4$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te x-1.

$$3x-3-\left(-x+1\right)=2\left(x+2\right)$$

Hei kimi i te tauaro o -x+1, kimihia te tauaro o ia taurangi.

$$3x-3-\left(-x\right)-1=2\left(x+2\right)$$

Tangohia te 1 i te -3, ka -4.

$$3x-4-\left(-x\right)=2\left(x+2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te x+2.

$$3x-4-\left(-x\right)=2x+4$$

Tangohia te 2x mai i ngā taha e rua.

$$3x-4-\left(-x\right)-2x=4$$

Pahekotia te 3x me -2x, ka x.

$$x-4-\left(-x\right)=4$$

Me tāpiri te 4 ki ngā taha e rua.

$$x-\left(-x\right)=4+4$$

Tāpirihia te 4 ki te 4, ka 8.

$$x-\left(-x\right)=8$$

Whakareatia te -1 ki te -1, ka 1.

$$x+x=8$$

Pahekotia te x me x, ka 2x.

$$2x=8$$

Whakawehea ngā taha e rua ki te 2.

$$x=\frac{8}{2}$$

Whakawehea te 8 ki te 2, kia riro ko 4.

$$x=4$$