Whakaoti i te 3^2+b^2=18

$$3 ^ { 2 } + b ^ { 2 } = 18$$

Whakaoti mō b

$$b=-3$$

$$b=3$$

Ngā Hipanga Whakamahi Rerekētanga o ngā Pūrua

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$9+b^{2}=18$$

Tangohia te 18 mai i ngā taha e rua.

$$9+b^{2}-18=0$$

Tangohia te 18 i te 9, ka -9.

$$-9+b^{2}=0$$

Whakaarohia te -9+b^{2}. Tuhia anō te -9+b^{2} hei b^{2}-3^{2}. Ka taea te rerekētanga o ngā pūrua te whakatauwehe mā te ture: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(b-3\right)\left(b+3\right)=0$$

Hei kimi otinga whārite, me whakaoti te b-3=0 me te b+3=0.

$$b=3 b=-3$$

Ngā Upane mā te Kimi Pūtakerua

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$9+b^{2}=18$$

Tangohia te 9 mai i ngā taha e rua.

$$b^{2}=18-9$$

Tangohia te 9 i te 18, ka 9.

$$b^{2}=9$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$b=3 b=-3$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tātaihia te 3 mā te pū o 2, kia riro ko 9.

$$9+b^{2}=18$$

Tangohia te 18 mai i ngā taha e rua.

$$9+b^{2}-18=0$$

Tangohia te 18 i te 9, ka -9.

$$-9+b^{2}=0$$

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$b^{2}-9=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -9 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$b=\frac{0±\sqrt{0^{2}-4\left(-9\right)}}{2}$$

Pūrua 0.

$$b=\frac{0±\sqrt{-4\left(-9\right)}}{2}$$

Whakareatia -4 ki te -9.

$$b=\frac{0±\sqrt{36}}{2}$$

Tuhia te pūtakerua o te 36.

$$b=\frac{0±6}{2}$$

Nā, me whakaoti te whārite b=\frac{0±6}{2} ina he tāpiri te ±. Whakawehe 6 ki te 2.

$$b=3$$

Nā, me whakaoti te whārite b=\frac{0±6}{2} ina he tango te ±. Whakawehe -6 ki te 2.

$$b=-3$$

Kua oti te whārite te whakatau.

$$b=3 b=-3$$