Whakaoti i te 3[x-2(x-1)]leq4x

$$3 [ x - 2 ( x - 1 ) ] \leq 4 x$$

Whakaoti mō x

$$x\geq \frac{6}{7}$$

Ngā Upane Otinga

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x-1.

$$3\left(x-2x+2\right)\leq 4x$$

Pahekotia te x me -2x, ka -x.

$$3\left(-x+2\right)\leq 4x$$

Whakamahia te āhuatanga tohatoha hei whakarea te 3 ki te -x+2.

$$-3x+6\leq 4x$$

Tangohia te 4x mai i ngā taha e rua.

$$-3x+6-4x\leq 0$$

Pahekotia te -3x me -4x, ka -7x.

$$-7x+6\leq 0$$

Tangohia te 6 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-7x\leq -6$$

Whakawehea ngā taha e rua ki te -7. I te mea he tōraro a -7, ka huri te ahunga koreōrite.

$$x\geq \frac{-6}{-7}$$

Ka taea te hautanga \frac{-6}{-7} te whakamāmā ki te \frac{6}{7} mā te tango tahi i te tohu tōraro i te taurunga me te tauraro.

$$x\geq \frac{6}{7}$$