Whakaoti i te 3=(-5a^2)(2-y)

$$3 = ( - 5 a ^ { 2 } ) ( 2 - y )$$

Whakaoti mō y

$$y=2+\frac{3}{5a^{2}}$$

$$a\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -5a^{2} ki te 2-y.

$$3=-10a^{2}+5a^{2}y$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$-10a^{2}+5a^{2}y=3$$

Me tāpiri te 10a^{2} ki ngā taha e rua.

$$5a^{2}y=3+10a^{2}$$

He hanga arowhānui tō te whārite.

$$5a^{2}y=10a^{2}+3$$

Whakawehea ngā taha e rua ki te 5a^{2}.

$$\frac{5a^{2}y}{5a^{2}}=\frac{10a^{2}+3}{5a^{2}}$$

Mā te whakawehe ki te 5a^{2} ka wetekia te whakareanga ki te 5a^{2}.

$$y=\frac{10a^{2}+3}{5a^{2}}$$

Whakawehe 3+10a^{2} ki te 5a^{2}.

$$y=2+\frac{3}{5a^{2}}$$

Whakaoti mō a

$$a=\frac{\sqrt{-\frac{15}{2-y}}}{5}$$

$$a=-\frac{\sqrt{-\frac{15}{2-y}}}{5}\text{, }y>2$$