Whakaoti mō x (complex solution)
x\in \mathrm{C}
Whakaoti mō x
x\in \mathrm{R}
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Tohaina
Kua tāruatia ki te papatopenga
2x-5\times \frac{2}{5}x+15=15
Whakamahia te āhuatanga tohatoha hei whakarea te -5 ki te \frac{2}{5}x-3.
2x-2x+15=15
Whakareatia -5 ki te \frac{2}{5}.
15=15
Pahekotia te 2x me -2x, ka 0.
\text{true}
Whakatauritea te 15 me te 15.
x\in \mathrm{C}
He pono tēnei mō tētahi x ahakoa.
2x-5\times \frac{2}{5}x+15=15
Whakamahia te āhuatanga tohatoha hei whakarea te -5 ki te \frac{2}{5}x-3.
2x-2x+15=15
Whakareatia -5 ki te \frac{2}{5}.
15=15
Pahekotia te 2x me -2x, ka 0.
\text{true}
Whakatauritea te 15 me te 15.
x\in \mathrm{R}
He pono tēnei mō tētahi x ahakoa.
Ngā Tauira
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
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