Whakaoti i te 2x-3=1/3(7x+2)

$$2x-3= \frac{ 1 }{ 3 } (7x+2)$$

Whakaoti mō x

$$x=-11$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te \frac{1}{3} ki te 7x+2.

$$2x-3=\frac{1}{3}\times 7x+\frac{1}{3}\times 2$$

Whakareatia te \frac{1}{3} ki te 7, ka \frac{7}{3}.

$$2x-3=\frac{7}{3}x+\frac{1}{3}\times 2$$

Whakareatia te \frac{1}{3} ki te 2, ka \frac{2}{3}.

$$2x-3=\frac{7}{3}x+\frac{2}{3}$$

Tangohia te \frac{7}{3}x mai i ngā taha e rua.

$$2x-3-\frac{7}{3}x=\frac{2}{3}$$

Pahekotia te 2x me -\frac{7}{3}x, ka -\frac{1}{3}x.

$$-\frac{1}{3}x-3=\frac{2}{3}$$

Me tāpiri te 3 ki ngā taha e rua.

$$-\frac{1}{3}x=\frac{2}{3}+3$$

Me tahuri te 3 ki te hautau \frac{9}{3}.

$$-\frac{1}{3}x=\frac{2}{3}+\frac{9}{3}$$

Tā te mea he rite te tauraro o \frac{2}{3} me \frac{9}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$-\frac{1}{3}x=\frac{2+9}{3}$$

Tāpirihia te 2 ki te 9, ka 11.

$$-\frac{1}{3}x=\frac{11}{3}$$

Me whakarea ngā taha e rua ki te -3, te tau utu o -\frac{1}{3}.

$$x=\frac{11}{3}\left(-3\right)$$

Tuhia te \frac{11}{3}\left(-3\right) hei hautanga kotahi.

$$x=\frac{11\left(-3\right)}{3}$$

Whakareatia te 11 ki te -3, ka -33.

$$x=\frac{-33}{3}$$

Whakawehea te -33 ki te 3, kia riro ko -11.

$$x=-11$$