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2 x = - 2

Whakaoti mō x

x = - 1

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Pātaitai

Linear Equation

2 x = - 2

Ngā Ataata

Let’s Solve The Linear Equation – Step by Step…

Step-by-step method of solving Linear Equations.

Linear Equations - Algebra

Ngā Raru Ōrite mai i te Rapu Tukutuku

12 x = - 4

https://www.tiger-algebra.com/drill/12x=-4/

12x=-4 One solution was found : x = -1/3 = -0.333 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

2 x = - 14

https://www.tiger-algebra.com/drill/2x=-14/

2x=-14 One solution was found : x = -7 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

2 x = - 16

https://www.tiger-algebra.com/drill/2x=-16/

2x=-16 One solution was found : x = -8 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : ...

Curves that share a tangent

https://math.stackexchange.com/q/1995052

Your idea is correct. With a bit different notation we have:

f (x) = x^{2} + 1 g (x) = - 2 x^{2} - 3

As you noted a common tangent is a line that passes thorough the points:

(x_{1}, f (x_{1})) (x_{2}, g (x_{2}))

Find inverse of

[- 2] m o d 5

https://math.stackexchange.com/questions/117919/find-inverse-of-2-bmod-5

You wrong in saying that

[42]_{5} = [- 2]_{5}

x

correctly, since

[42]_{5} [- 2]_{5} = [2]_{5} [3]_{5} = [6]_{5} = [1]_{5}

, although since we are working mod 5 it is traditional to choose the representative ...

2^{∣ x + 2 ∣} - ∣ 2^{x + 1} - 1 ∣ = 2^{x + 1} + 1

https://math.stackexchange.com/questions/2807159/solve-2x2-2x1-1-2x11

x < - 2

, the equation becomes

2^{- (x + 2)} + 2^{x + 1} - 1 = 2^{x + 1} + 1

2^{- (x + 2)} = 2

- (x + 2) = 1

x + 2 = - 1

x = - 3

x \geq - 1

2^{x + 2} - 2^{x + 1} + 1 = 2^{x + 1} + 1

2^{x + 2} = 2 \cdot 2^{x + 1} = 2^{x + 2}

Tohaina

Kua tāruatia ki te papatopenga

x=\frac{-2}{2}

Whakawehea ngā taha e rua ki te 2.

x=-1

Whakawehea te -2 ki te 2, kia riro ko -1.

Ngā Tauira

whārite tapawhā

x^{2} - 4 x - 5 = 0

4 sin θ cos θ = 2 sin θ

whārite paerangi

y = 3 x + 4

699 * 533

[2534] [2 - 1 0135]

whārite Simultaneous

{8 x + 2 y = 46 7 x + 3 y = 47

Whakarerekētanga

\frac{d}{d x} \frac{( 3 x ^{2} - 2 )}{( x - 5 )}

\int_{0}^{1} x e^{- x^{2}} d x

x \to - 3 lim \frac{x ^{2} - 9}{x ^{2} + 2 x - 3}