Whakaoti i te 2x+4y-62=x+y-23

$$2x+4y-62=x+y-23$$

Whakaoti mō x

$$x=39-3y$$

Ngā Upane Otinga

Tangohia te x mai i ngā taha e rua.

$$2x+4y-62-x=y-23$$

Pahekotia te 2x me -x, ka x.

$$x+4y-62=y-23$$

Tangohia te 4y mai i ngā taha e rua.

$$x-62=y-23-4y$$

Pahekotia te y me -4y, ka -3y.

$$x-62=-3y-23$$

Me tāpiri te 62 ki ngā taha e rua.

$$x=-3y-23+62$$

Tāpirihia te -23 ki te 62, ka 39.

$$x=-3y+39$$

Whakaoti mō y

$$y=-\frac{x}{3}+13$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te y mai i ngā taha e rua.

$$2x+4y-62-y=x-23$$

Pahekotia te 4y me -y, ka 3y.

$$2x+3y-62=x-23$$

Tangohia te 2x mai i ngā taha e rua.

$$3y-62=x-23-2x$$

Pahekotia te x me -2x, ka -x.

$$3y-62=-x-23$$

Me tāpiri te 62 ki ngā taha e rua.

$$3y=-x-23+62$$

Tāpirihia te -23 ki te 62, ka 39.

$$3y=-x+39$$

He hanga arowhānui tō te whārite.

$$3y=39-x$$

Whakawehea ngā taha e rua ki te 3.

$$\frac{3y}{3}=\frac{39-x}{3}$$

Mā te whakawehe ki te 3 ka wetekia te whakareanga ki te 3.

$$y=\frac{39-x}{3}$$

Whakawehe -x+39 ki te 3.

$$y=-\frac{x}{3}+13$$