Whakaoti i te 28.00*100000000000000000000000000000000000000000000==

28.00 \times 100000000000000000000000000000000000000000000==

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2800000000000000000000000000000000000000000000

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28.00 \times 100000000000000000000000000000000000000000000==

Whakareatia te 28 ki te 100000000000000000000000000000000000000000000, ka 2800000000000000000000000000000000000000000000.

2800000000000000000000000000000000000000000000

Tauwehe

2^{46}\times 5^{44}\times 7

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5 raruraru e ōrite ana ki:

28.00 \times 100000000000000000000000000000000000000000000==

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You want to change your cell phone service. The new company charges 40 per month for cell phone use. There is a one-time start-up fee of 25. Which equation shows the total cost of your cell phone ...

https://brainly.com/question/2983009

25+40*t=cT=time,c=cost over time

Regression marginal effects

https://stats.stackexchange.com/q/43309

The marginal effect of experience on wage is the derivative b1 + 2(b2)(exper), and varies with the number of years experience. For 10 years experience, the Marginal calculation should therefore be: ...

Conjugate mixture of beta distributions - weights

https://stats.stackexchange.com/questions/100717/conjugate-mixture-of-beta-distributions-weights

Assuming you meant a binomial likelihood, \begin{eqnarray*} \text{Posterior}(\theta) & \propto & \text{Likelihood}(\theta) \times \text{Prior}(\theta) \\ \\ & = & \text{Binomial}(20 \mid 30, \theta) \times \bigg[ \lambda \times \text{Beta}(\theta \mid 20,10) + (1-\lambda) \times \text{Beta}(\theta \mid 20, 20) \bigg] \\ \\ & = & \lambda \times \text{Binomial}(20 \mid 30, \theta) \times \text{Beta}(\theta \mid 20,10) \\[8pt] &&+ (1 - \lambda) \times \text{Binomial}(20 \mid 30, \theta) \times \text{Beta}(\theta \mid 20,20) \\ \\ & = & \lambda { 30 \choose 20} \frac{1}{\text{B}(20, 10)} \theta^{40 - 1} (1-\theta)^{20-1} \\[8pt] &&+ (1-\lambda) {30 \choose 20} \frac{1}{\text{B}(20,20)} \theta^{40-1} (1-\theta)^{30-1} \\ \\ & = & \lambda { 30 \choose 20} \frac{\text{B}(40,20) \text{B}(40,30)}{\text{B}(20, 10) \text{B}(40,20) \text{B}(40,30)} \theta^{40 - 1} (1-\theta)^{20-1} \\[8pt] &&+ (1-\lambda) {30 \choose 20} \frac{\text{B}(40,20) \text{B}(40,30)}{\text{B}(20,20) \text{B}(40,20) \text{B}(40,30)} \theta^{40-1} (1-\theta)^{30-1} \\ \\ & = & \lambda { 30 \choose 20} \frac{ \text{B}(40,20)}{\text{B}(20, 10)} \text{Beta}(\theta \mid 40,20) \\[8pt] &&+ (1- \lambda) { 30 \choose 20} \frac{\text{B}(40,30)}{\text{B}(20, 20)} \text{Beta}(\theta \mid 40,30) \\ \\ & \propto & \lambda \frac{ \text{B}(40,20)}{\text{B}(20, 10)} \text{Beta}(\theta \mid 40,20) \\[8pt] &&+ (1- \lambda) \frac{\text{B}(40,30)}{\text{B}(20, 20)} \text{Beta}(\theta \mid 40,30). \end{eqnarray*} ...

Proof of Yang's theorem

https://physics.stackexchange.com/questions/38427/proof-of-yangs-theorem

Because \mathcal{M}_3 as written above actually vanishes by a simple vector identity. On the first term, write (\vec{\epsilon}_V\times\vec\epsilon_1).\vec\epsilon_2=(\vec\epsilon_2\times\vec\epsilon_V).\vec\epsilon_1 ...

Find all solutions using the Chinese Remainder Theorem

https://math.stackexchange.com/questions/2149313/find-all-solutions-using-the-chinese-remainder-theorem

Generally it is easier to solve them a pair at a time, as follows. {\rm mod}\ 25\!:\,\ 7\equiv x\iff x = 7+25j\, for some integer j {\rm mod}\ 21\!:\,\ 5 \equiv x\equiv 7+25j\equiv 7+4j\!\iff\! 4j\equiv -2\!\iff\! 2j \equiv -1\equiv 20 \!\iff\! j \equiv \color{#c00}{10} ...

How do I find the following probabilities? (The details are below)

https://math.stackexchange.com/q/1658029

a. Your calculation is correct. b. Pr(\text{from A}|\text{defective}) = \frac{Pr(\text{defective}|\text{from A})Pr(\text{from A})}{Pr(\text{defective})} = \frac{0.02(0.7)}{0.029} = \frac{14}{29} = 0.4827586 ...

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2800000000000000000000000000000000000000000000

Whakareatia te 28 ki te 100000000000000000000000000000000000000000000, ka 2800000000000000000000000000000000000000000000.

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whārite tapawhā

{ x } ^ { 2 } - 4 x - 5 = 0

Āhuahanga

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

whārite Simultaneous

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Whakarerekētanga

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

Whakaurunga

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Ngā Tepe

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

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