Whakaoti i te 27+3+10+6*-6x+27geq10

$$27 + 3 + 10 + 6 \times - 6 x + 27 \geq 10$$

Whakaoti mō x

$$x\leq \frac{19}{12}$$

Ngā Upane Otinga

Tāpirihia te 27 ki te 3, ka 30.

$$30+10+6\left(-6\right)x+27\geq 10$$

Tāpirihia te 30 ki te 10, ka 40.

$$40+6\left(-6\right)x+27\geq 10$$

Whakareatia te 6 ki te -6, ka -36.

$$40-36x+27\geq 10$$

Tāpirihia te 40 ki te 27, ka 67.

$$67-36x\geq 10$$

Tangohia te 67 mai i ngā taha e rua.

$$-36x\geq 10-67$$

Tangohia te 67 i te 10, ka -57.

$$-36x\geq -57$$

Whakawehea ngā taha e rua ki te -36. I te mea he tōraro a -36, ka huri te ahunga koreōrite.

$$x\leq \frac{-57}{-36}$$

Whakahekea te hautanga \frac{-57}{-36} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te -3.

$$x\leq \frac{19}{12}$$