Whakaoti i te 27+3+10+6^5x-6x+27geq10

$$27 + 3 + 10 + 6 ^ { 5 } x - 6 x + 27 \geq 10$$

Whakaoti mō x

$$x\geq -\frac{19}{2590}$$

Ngā Upane Otinga

Tāpirihia te 27 ki te 3, ka 30.

$$30+10+6^{5}x-6x+27\geq 10$$

Tāpirihia te 30 ki te 10, ka 40.

$$40+6^{5}x-6x+27\geq 10$$

Tātaihia te 6 mā te pū o 5, kia riro ko 7776.

$$40+7776x-6x+27\geq 10$$

Pahekotia te 7776x me -6x, ka 7770x.

$$40+7770x+27\geq 10$$

Tāpirihia te 40 ki te 27, ka 67.

$$67+7770x\geq 10$$

Tangohia te 67 mai i ngā taha e rua.

$$7770x\geq 10-67$$

Tangohia te 67 i te 10, ka -57.

$$7770x\geq -57$$

Whakawehea ngā taha e rua ki te 7770. I te mea he tōrunga te 7770, kāore e huri te ahunga koreōrite.

$$x\geq \frac{-57}{7770}$$

Whakahekea te hautanga \frac{-57}{7770} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 3.

$$x\geq -\frac{19}{2590}$$