Whakaoti i te 26y^2=48

$$26 y ^ { 2 } = 48$$

Whakaoti mō y

$$y = \frac{2 \sqrt{78}}{13} \approx 1.358732441$$

$$y = -\frac{2 \sqrt{78}}{13} \approx -1.358732441$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 26.

$$y^{2}=\frac{48}{26}$$

Whakahekea te hautanga \frac{48}{26} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$y^{2}=\frac{24}{13}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$y=\frac{2\sqrt{78}}{13} y=-\frac{2\sqrt{78}}{13}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakawehea ngā taha e rua ki te 26.

$$y^{2}=\frac{48}{26}$$

Whakahekea te hautanga \frac{48}{26} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$y^{2}=\frac{24}{13}$$

Tangohia te \frac{24}{13} mai i ngā taha e rua.

$$y^{2}-\frac{24}{13}=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -\frac{24}{13} mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\left(-\frac{24}{13}\right)}}{2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\left(-\frac{24}{13}\right)}}{2}$$

Whakareatia -4 ki te -\frac{24}{13}.

$$y=\frac{0±\sqrt{\frac{96}{13}}}{2}$$

Tuhia te pūtakerua o te \frac{96}{13}.

$$y=\frac{0±\frac{4\sqrt{78}}{13}}{2}$$

Nā, me whakaoti te whārite y=\frac{0±\frac{4\sqrt{78}}{13}}{2} ina he tāpiri te ±.

$$y=\frac{2\sqrt{78}}{13}$$

Nā, me whakaoti te whārite y=\frac{0±\frac{4\sqrt{78}}{13}}{2} ina he tango te ±.

$$y=-\frac{2\sqrt{78}}{13}$$

Kua oti te whārite te whakatau.

$$y=\frac{2\sqrt{78}}{13} y=-\frac{2\sqrt{78}}{13}$$