Tīpoka ki ngā ihirangi matua
Kimi Pārōnaki e ai ki x
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\frac{\mathrm{d}}{\mathrm{d}x}(62x)
Pahekotia te 26x me 36x, ka 62x.
62x^{1-1}
Ko te pārōnaki o ax^{n} ko nax^{n-1}.
62x^{0}
Tango 1 mai i 1.
62\times 1
Mō tētahi kupu t mahue te 0, t^{0}=1.
62
Mō tētahi kupu t, t\times 1=t me 1t=t.
62x
Pahekotia te 26x me 36x, ka 62x.