Whakaoti i te 25(1-x)^2=16

$$25 ( 1 - x ) ^ { 2 } = 16$$

Whakaoti mō x

$$x=\frac{1}{5}=0.2$$

$$x = \frac{9}{5} = 1\frac{4}{5} = 1.8$$

Ngā Upane mā te Kimi Pūtakerua

Whakawehea ngā taha e rua ki te 25.

$$\frac{25\left(-x+1\right)^{2}}{25}=\frac{16}{25}$$

Mā te whakawehe ki te 25 ka wetekia te whakareanga ki te 25.

$$\left(-x+1\right)^{2}=\frac{16}{25}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$-x+1=\frac{4}{5} -x+1=-\frac{4}{5}$$

Me tango 1 mai i ngā taha e rua o te whārite.

$$-x+1-1=\frac{4}{5}-1 -x+1-1=-\frac{4}{5}-1$$

Mā te tango i te 1 i a ia ake anō ka toe ko te 0.

$$-x=\frac{4}{5}-1 -x=-\frac{4}{5}-1$$

Tango 1 mai i \frac{4}{5}.

$$-x=-\frac{1}{5}$$

Tango 1 mai i -\frac{4}{5}.

$$-x=-\frac{9}{5}$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-x}{-1}=-\frac{\frac{1}{5}}{-1} \frac{-x}{-1}=-\frac{\frac{9}{5}}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$x=-\frac{\frac{1}{5}}{-1} x=-\frac{\frac{9}{5}}{-1}$$

Whakawehe -\frac{1}{5} ki te -1.

$$x=\frac{1}{5}$$

Whakawehe -\frac{9}{5} ki te -1.

$$x=\frac{9}{5}$$

Kua oti te whārite te whakatau.

$$x=\frac{1}{5} x=\frac{9}{5}$$