Whakaoti i te 25x^2-10x+800

$$25 { x }^{ 2 } -10x+800$$

Tauwehe

$$5\left(5x^{2}-2x+160\right)$$

Ngā Upane Otinga

Tauwehea te 5. Kāore te pūrau 5x^{2}-2x+160 i whakatauwehea i te mea kāhore ōna pūtake whakahau.

$$5\left(5x^{2}-2x+160\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$25x^{2}-10x+800=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$x=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}-4\times 25\times 800}}{2\times 25}$$

Pūrua -10.

$$x=\frac{-\left(-10\right)±\sqrt{100-4\times 25\times 800}}{2\times 25}$$

Whakareatia -4 ki te 25.

$$x=\frac{-\left(-10\right)±\sqrt{100-100\times 800}}{2\times 25}$$

Whakareatia -100 ki te 800.

$$x=\frac{-\left(-10\right)±\sqrt{100-80000}}{2\times 25}$$

Tāpiri 100 ki te -80000.

$$x=\frac{-\left(-10\right)±\sqrt{-79900}}{2\times 25}$$

Tā te mea e kore te pūrua o tētahi tau tōraro e tautohutia ki te āpure tūturu, kāhore he rongoā. Kāore e taea te pūrau pūrua te whakatauwehe.

$$25x^{2}-10x+800$$

Aromātai

$$25x^{2}-10x+800$$