Whakaoti i te 24x^2+16xy+8=84

$$24 { x }^{ 2 } +16xy+8=84$$

Whakaoti mō y

$$y=-\frac{3x}{2}+\frac{19}{4x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 24x^{2} mai i ngā taha e rua.

$$16xy+8=84-24x^{2}$$

Tangohia te 8 mai i ngā taha e rua.

$$16xy=84-24x^{2}-8$$

Tangohia te 8 i te 84, ka 76.

$$16xy=76-24x^{2}$$

Whakawehea ngā taha e rua ki te 16x.

$$\frac{16xy}{16x}=\frac{76-24x^{2}}{16x}$$

Mā te whakawehe ki te 16x ka wetekia te whakareanga ki te 16x.

$$y=\frac{76-24x^{2}}{16x}$$

Whakawehe 76-24x^{2} ki te 16x.

$$y=-\frac{3x}{2}+\frac{19}{4x}$$

Whakaoti mō x

$$x=\frac{\sqrt{4y^{2}+114}}{6}-\frac{y}{3}$$

$$x=-\frac{\sqrt{4y^{2}+114}}{6}-\frac{y}{3}$$