Whakaoti i te 22*5=4*9t^2

$$22 \cdot 5 = 4 \cdot 9 t ^ { 2 }$$

Whakaoti mō t

$$t = \frac{\sqrt{110}}{6} \approx 1.748014747$$

$$t = -\frac{\sqrt{110}}{6} \approx -1.748014747$$

Ngā Upane mā te Kimi Pūtakerua

Whakareatia te 22 ki te 5, ka 110.

$$110=4\times 9t^{2}$$

Whakareatia te 4 ki te 9, ka 36.

$$110=36t^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$36t^{2}=110$$

Whakawehea ngā taha e rua ki te 36.

$$t^{2}=\frac{110}{36}$$

Whakahekea te hautanga \frac{110}{36} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$t^{2}=\frac{55}{18}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$t=\frac{\sqrt{110}}{6} t=-\frac{\sqrt{110}}{6}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Whakareatia te 22 ki te 5, ka 110.

$$110=4\times 9t^{2}$$

Whakareatia te 4 ki te 9, ka 36.

$$110=36t^{2}$$

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$36t^{2}=110$$

Tangohia te 110 mai i ngā taha e rua.

$$36t^{2}-110=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 36 mō a, 0 mō b, me -110 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$t=\frac{0±\sqrt{0^{2}-4\times 36\left(-110\right)}}{2\times 36}$$

Pūrua 0.

$$t=\frac{0±\sqrt{-4\times 36\left(-110\right)}}{2\times 36}$$

Whakareatia -4 ki te 36.

$$t=\frac{0±\sqrt{-144\left(-110\right)}}{2\times 36}$$

Whakareatia -144 ki te -110.

$$t=\frac{0±\sqrt{15840}}{2\times 36}$$

Tuhia te pūtakerua o te 15840.

$$t=\frac{0±12\sqrt{110}}{2\times 36}$$

Whakareatia 2 ki te 36.

$$t=\frac{0±12\sqrt{110}}{72}$$

Nā, me whakaoti te whārite t=\frac{0±12\sqrt{110}}{72} ina he tāpiri te ±.

$$t=\frac{\sqrt{110}}{6}$$

Nā, me whakaoti te whārite t=\frac{0±12\sqrt{110}}{72} ina he tango te ±.

$$t=-\frac{\sqrt{110}}{6}$$

Kua oti te whārite te whakatau.

$$t=\frac{\sqrt{110}}{6} t=-\frac{\sqrt{110}}{6}$$