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Whakaoti mō x
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Whakaoti mō x (complex solution)
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Tohaina

\frac{20}{50}=0.92^{x}
Whakawehea ngā taha e rua ki te 50.
\frac{2}{5}=0.92^{x}
Whakahekea te hautanga \frac{20}{50} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 10.
0.92^{x}=\frac{2}{5}
Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.
\log(0.92^{x})=\log(\frac{2}{5})
Tuhia te tau taupū kōaro o ngā taha e rua o te whārite.
x\log(0.92)=\log(\frac{2}{5})
Ko te taupū kōaro o tētahi tau ka hīkina ki tētahi pū ko te pū whakarea ki te taupū kōaro o taua tau.
x=\frac{\log(\frac{2}{5})}{\log(0.92)}
Whakawehea ngā taha e rua ki te \log(0.92).
x=\log_{0.92}\left(\frac{2}{5}\right)
Mā te tikanga tātai huri pūtake \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).