Whakaoti i te 2-xleft(3x-2left(x-2right)right)=1-left(x+1right)left(x-2right)

$$2-x \left( 3x-2 \left( x-2 \right) \right) = 1- \left( x+1 \right) \left( x-2 \right)$$

Whakaoti mō x

$$x=-\frac{1}{5}=-0.2$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -2 ki te x-2.

$$2-x\left(3x-2x+4\right)=1-\left(x+1\right)\left(x-2\right)$$

Pahekotia te 3x me -2x, ka x.

$$2-x\left(x+4\right)=1-\left(x+1\right)\left(x-2\right)$$

Whakamahia te āhuatanga tohatoha hei whakarea te x ki te x+4.

$$2-\left(x^{2}+4x\right)=1-\left(x+1\right)\left(x-2\right)$$

Hei kimi i te tauaro o x^{2}+4x, kimihia te tauaro o ia taurangi.

$$2-x^{2}-4x=1-\left(x+1\right)\left(x-2\right)$$

Whakamahia te āhuatanga tuaritanga hei whakarea te x+1 ki te x-2 ka whakakotahi i ngā kupu rite.

$$2-x^{2}-4x=1-\left(x^{2}-x-2\right)$$

Hei kimi i te tauaro o x^{2}-x-2, kimihia te tauaro o ia taurangi.

$$2-x^{2}-4x=1-x^{2}+x+2$$

Tāpirihia te 1 ki te 2, ka 3.

$$2-x^{2}-4x=3-x^{2}+x$$

Me tāpiri te x^{2} ki ngā taha e rua.

$$2-x^{2}-4x+x^{2}=3+x$$

Pahekotia te -x^{2} me x^{2}, ka 0.

$$2-4x=3+x$$

Tangohia te x mai i ngā taha e rua.

$$2-4x-x=3$$

Pahekotia te -4x me -x, ka -5x.

$$2-5x=3$$

Tangohia te 2 mai i ngā taha e rua.

$$-5x=3-2$$

Tangohia te 2 i te 3, ka 1.

$$-5x=1$$

Whakawehea ngā taha e rua ki te -5.

$$x=\frac{1}{-5}$$

Ka taea te hautanga \frac{1}{-5} te tuhi anō ko -\frac{1}{5} mā te tango i te tohu tōraro.

$$x=-\frac{1}{5}$$