Whakaoti i te 2(x1)-15=5(x4)+53=

$$2(x1)-15=5(x4)+53=$$

Whakaoti mō x_1

$$x_{1}=\frac{5x_{4}}{2}+34$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Me tāpiri te 15 ki ngā taha e rua.

$$2x_{1}=5x_{4}+53+15$$

Tāpirihia te 53 ki te 15, ka 68.

$$2x_{1}=5x_{4}+68$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2x_{1}}{2}=\frac{5x_{4}+68}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$x_{1}=\frac{5x_{4}+68}{2}$$

Whakawehe 5x_{4}+68 ki te 2.

$$x_{1}=\frac{5x_{4}}{2}+34$$

Whakaoti mō x_4

$$x_{4}=\frac{2\left(x_{1}-34\right)}{5}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawhitihia ngā taha kia puta ki te taha mauī ngā kīanga tau taurangi katoa.

$$5x_{4}+53=2x_{1}-15$$

Tangohia te 53 mai i ngā taha e rua.

$$5x_{4}=2x_{1}-15-53$$

Tangohia te 53 i te -15, ka -68.

$$5x_{4}=2x_{1}-68$$

Whakawehea ngā taha e rua ki te 5.

$$\frac{5x_{4}}{5}=\frac{2x_{1}-68}{5}$$

Mā te whakawehe ki te 5 ka wetekia te whakareanga ki te 5.

$$x_{4}=\frac{2x_{1}-68}{5}$$