Whakaoti i te 2(3x(2-4)+2x-5(x+1))=-28

$$2(3x(2-4)+2x-5(x+1))=-28$$

Whakaoti mō x

$$x=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakawehea ngā taha e rua ki te 2.

$$3x\left(2-4\right)+2x-5\left(x+1\right)=\frac{-28}{2}$$

Whakawehea te -28 ki te 2, kia riro ko -14.

$$3x\left(2-4\right)+2x-5\left(x+1\right)=-14$$

Tangohia te 4 i te 2, ka -2.

$$3x\left(-2\right)+2x-5\left(x+1\right)=-14$$

Whakareatia te 3 ki te -2, ka -6.

$$-6x+2x-5\left(x+1\right)=-14$$

Pahekotia te -6x me 2x, ka -4x.

$$-4x-5\left(x+1\right)=-14$$

Whakamahia te āhuatanga tohatoha hei whakarea te -5 ki te x+1.

$$-4x-5x-5=-14$$

Pahekotia te -4x me -5x, ka -9x.

$$-9x-5=-14$$

Me tāpiri te 5 ki ngā taha e rua.

$$-9x=-14+5$$

Tāpirihia te -14 ki te 5, ka -9.

$$-9x=-9$$

Whakawehea ngā taha e rua ki te -9.

$$x=\frac{-9}{-9}$$

Whakawehea te -9 ki te -9, kia riro ko 1.

$$x=1$$