Whakaoti i te 2(1-x)-3(2x-1)-(1+x)=8

$$2(1-x)-3(2x-1)-(1+x)=8$$

Whakaoti mō x

$$x=-\frac{4}{9}\approx -0.444444444$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2 ki te 1-x.

$$2-2x-3\left(2x-1\right)-\left(1+x\right)=8$$

Whakamahia te āhuatanga tohatoha hei whakarea te -3 ki te 2x-1.

$$2-2x-6x+3-\left(1+x\right)=8$$

Pahekotia te -2x me -6x, ka -8x.

$$2-8x+3-\left(1+x\right)=8$$

Tāpirihia te 2 ki te 3, ka 5.

$$5-8x-\left(1+x\right)=8$$

Hei kimi i te tauaro o 1+x, kimihia te tauaro o ia taurangi.

$$5-8x-1-x=8$$

Tangohia te 1 i te 5, ka 4.

$$4-8x-x=8$$

Pahekotia te -8x me -x, ka -9x.

$$4-9x=8$$

Tangohia te 4 mai i ngā taha e rua.

$$-9x=8-4$$

Tangohia te 4 i te 8, ka 4.

$$-9x=4$$

Whakawehea ngā taha e rua ki te -9.

$$x=\frac{4}{-9}$$

Ka taea te hautanga \frac{4}{-9} te tuhi anō ko -\frac{4}{9} mā te tango i te tohu tōraro.

$$x=-\frac{4}{9}$$