Whakaoti i te 2y1(x-1/3)-sqrt{2}=0

$$2 y 1 ( x - \frac { 1 } { 3 } ) - \sqrt { 2 } = 0$$

Whakaoti mō x

$$x=\frac{1}{3}+\frac{\sqrt{2}}{2y_{1}}$$

$$y_{1}\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2y_{1} ki te x-\frac{1}{3}.

$$2y_{1}x-\frac{2}{3}y_{1}-\sqrt{2}=0$$

Me tāpiri te \frac{2}{3}y_{1} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$2y_{1}x-\sqrt{2}=\frac{2}{3}y_{1}$$

Me tāpiri te \sqrt{2} ki ngā taha e rua.

$$2y_{1}x=\frac{2}{3}y_{1}+\sqrt{2}$$

He hanga arowhānui tō te whārite.

$$2y_{1}x=\frac{2y_{1}}{3}+\sqrt{2}$$

Whakawehea ngā taha e rua ki te 2y_{1}.

$$\frac{2y_{1}x}{2y_{1}}=\frac{\frac{2y_{1}}{3}+\sqrt{2}}{2y_{1}}$$

Mā te whakawehe ki te 2y_{1} ka wetekia te whakareanga ki te 2y_{1}.

$$x=\frac{\frac{2y_{1}}{3}+\sqrt{2}}{2y_{1}}$$

Whakawehe \frac{2y_{1}}{3}+\sqrt{2} ki te 2y_{1}.

$$x=\frac{1}{3}+\frac{\sqrt{2}}{2y_{1}}$$

Whakaoti mō y_1

$$y_{1}=\frac{3\sqrt{2}}{2\left(3x-1\right)}$$

$$x\neq \frac{1}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 2y_{1} ki te x-\frac{1}{3}.

$$2y_{1}x-\frac{2}{3}y_{1}-\sqrt{2}=0$$

Me tāpiri te \sqrt{2} ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$2y_{1}x-\frac{2}{3}y_{1}=\sqrt{2}$$

Pahekotia ngā kīanga tau katoa e whai ana i te y_{1}.

$$\left(2x-\frac{2}{3}\right)y_{1}=\sqrt{2}$$

Whakawehea ngā taha e rua ki te 2x-\frac{2}{3}.

$$\frac{\left(2x-\frac{2}{3}\right)y_{1}}{2x-\frac{2}{3}}=\frac{\sqrt{2}}{2x-\frac{2}{3}}$$

Mā te whakawehe ki te 2x-\frac{2}{3} ka wetekia te whakareanga ki te 2x-\frac{2}{3}.

$$y_{1}=\frac{\sqrt{2}}{2x-\frac{2}{3}}$$

Whakawehe \sqrt{2} ki te 2x-\frac{2}{3}.

$$y_{1}=\frac{3\sqrt{2}}{2\left(3x-1\right)}$$