Whakaoti i te 2y^2+2=0

$$2 y ^ { 2 } + 2 = 0$$

Whakaoti mō y

$$y=-i$$

$$y=i$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$2y^{2}=-2$$

Whakawehea ngā taha e rua ki te 2.

$$y^{2}=\frac{-2}{2}$$

Whakawehea te -2 ki te 2, kia riro ko -1.

$$y^{2}=-1$$

Kua oti te whārite te whakatau.

$$y=i y=-i$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$2y^{2}+2=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 0 mō b, me 2 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$y=\frac{0±\sqrt{0^{2}-4\times 2\times 2}}{2\times 2}$$

Pūrua 0.

$$y=\frac{0±\sqrt{-4\times 2\times 2}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$y=\frac{0±\sqrt{-8\times 2}}{2\times 2}$$

Whakareatia -8 ki te 2.

$$y=\frac{0±\sqrt{-16}}{2\times 2}$$

Tuhia te pūtakerua o te -16.

$$y=\frac{0±4i}{2\times 2}$$

Whakareatia 2 ki te 2.

$$y=\frac{0±4i}{4}$$

Nā, me whakaoti te whārite y=\frac{0±4i}{4} ina he tāpiri te ±.

$$y=i$$

Nā, me whakaoti te whārite y=\frac{0±4i}{4} ina he tango te ±.

$$y=-i$$

Kua oti te whārite te whakatau.

$$y=i y=-i$$