Whakaoti i te 2x^{2}-x^3+3x^3-x-x^3+4x+3-5x^2=

$$2 x ^ { 2 } - x ^ { 3 } + 3 x ^ { 3 } - x - x ^ { 3 } + 4 x + 3 - 5 x ^ { 2 } =$$

Aromātai

$$x^{3}-3x^{2}+3x+3$$

Ngā Upane Otinga

Pahekotia te -x^{3} me 3x^{3}, ka 2x^{3}.

$$2x^{2}+2x^{3}-x-x^{3}+4x+3-5x^{2}$$

Pahekotia te 2x^{3} me -x^{3}, ka x^{3}.

$$2x^{2}+x^{3}-x+4x+3-5x^{2}$$

Pahekotia te -x me 4x, ka 3x.

$$2x^{2}+x^{3}+3x+3-5x^{2}$$

Pahekotia te 2x^{2} me -5x^{2}, ka -3x^{2}.

$$-3x^{2}+x^{3}+3x+3$$

Kimi Pārōnaki e ai ki x

$$3\left(x-1\right)^{2}$$

Ngā Upane e Whakamahi ana i te Ture Pārōnaki mō te Tapeke

Pahekotia te -x^{3} me 3x^{3}, ka 2x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+2x^{3}-x-x^{3}+4x+3-5x^{2})$$

Pahekotia te 2x^{3} me -x^{3}, ka x^{3}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+x^{3}-x+4x+3-5x^{2})$$

Pahekotia te -x me 4x, ka 3x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{2}+x^{3}+3x+3-5x^{2})$$

Pahekotia te 2x^{2} me -5x^{2}, ka -3x^{2}.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-3x^{2}+x^{3}+3x+3)$$

Ko te pārōnaki o tētahi pūrau ko te tapeke o ngā pārōnaki o ōna kīanga tau. Ko te pārōnaki o tētahi kīanga tau pūmau ko 0. Ko te pārōnaki o te ax^{n} ko te nax^{n-1}.

$$2\left(-3\right)x^{2-1}+3x^{3-1}+3x^{1-1}$$

Whakareatia 2 ki te -3.

$$-6x^{2-1}+3x^{3-1}+3x^{1-1}$$

Tango 1 mai i 2.

$$-6x^{1}+3x^{3-1}+3x^{1-1}$$

Tango 1 mai i 3.

$$-6x^{1}+3x^{2}+3x^{1-1}$$

Tango 1 mai i 1.

$$-6x^{1}+3x^{2}+3x^{0}$$

Mō tētahi kupu t, t^{1}=t.

$$-6x+3x^{2}+3x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$-6x+3x^{2}+3\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$-6x+3x^{2}+3$$