Whakaoti i te 2x^2-4=0

$$2 x ^ { 2 } - 4 = 0$$

Whakaoti mō x

$$x=\sqrt{2}\approx 1.414213562$$

$$x=-\sqrt{2}\approx -1.414213562$$

Ngā Upane mā te Kimi Pūtakerua

Me tāpiri te 4 ki ngā taha e rua. Ko te tau i tāpiria he kore ka hua koia tonu.

$$2x^{2}=4$$

Whakawehea ngā taha e rua ki te 2.

$$x^{2}=\frac{4}{2}$$

Whakawehea te 4 ki te 2, kia riro ko 2.

$$x^{2}=2$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\sqrt{2} x=-\sqrt{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā tikanga tātai pūrua pēnei i tēnei nā, me te kīanga tau x^{2} engari kāore he kīanga tau x, ka taea tonu te whakaoti mā te whakamahi i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, ina tuhia ki te tānga ngahuru: ax^{2}+bx+c=0.

$$2x^{2}-4=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 0 mō b, me -4 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-4\right)}}{2\times 2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2\left(-4\right)}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8\left(-4\right)}}{2\times 2}$$

Whakareatia -8 ki te -4.

$$x=\frac{0±\sqrt{32}}{2\times 2}$$

Tuhia te pūtakerua o te 32.

$$x=\frac{0±4\sqrt{2}}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{0±4\sqrt{2}}{4}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}}{4} ina he tāpiri te ±.

$$x=\sqrt{2}$$

Nā, me whakaoti te whārite x=\frac{0±4\sqrt{2}}{4} ina he tango te ±.

$$x=-\sqrt{2}$$

Kua oti te whārite te whakatau.

$$x=\sqrt{2} x=-\sqrt{2}$$