Whakaoti i te 2x^2-13x=0

$$2 x ^ { 2 } - 13 x = 0$$

Whakaoti mō x

$$x = \frac{13}{2} = 6\frac{1}{2} = 6.5$$

$$x=0$$

Ngā Upane Whakamahi Tauwehe

Tauwehea te x.

$$x\left(2x-13\right)=0$$

Hei kimi otinga whārite, me whakaoti te x=0 me te 2x-13=0.

$$x=0 x=\frac{13}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$2x^{2}-13x=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, -13 mō b, me 0 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-13\right)±\sqrt{\left(-13\right)^{2}}}{2\times 2}$$

Tuhia te pūtakerua o te \left(-13\right)^{2}.

$$x=\frac{-\left(-13\right)±13}{2\times 2}$$

Ko te tauaro o -13 ko 13.

$$x=\frac{13±13}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{13±13}{4}$$

Nā, me whakaoti te whārite x=\frac{13±13}{4} ina he tāpiri te ±. Tāpiri 13 ki te 13.

$$x=\frac{26}{4}$$

Whakahekea te hautanga \frac{26}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{13}{2}$$

Nā, me whakaoti te whārite x=\frac{13±13}{4} ina he tango te ±. Tango 13 mai i 13.

$$x=\frac{0}{4}$$

Whakawehe 0 ki te 4.

$$x=0$$

Kua oti te whārite te whakatau.

$$x=\frac{13}{2} x=0$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$2x^{2}-13x=0$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2x^{2}-13x}{2}=\frac{0}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$x^{2}-\frac{13}{2}x=\frac{0}{2}$$

Whakawehe 0 ki te 2.

$$x^{2}-\frac{13}{2}x=0$$

Whakawehea te -\frac{13}{2}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te -\frac{13}{4}. Nā, tāpiria te pūrua o te -\frac{13}{4} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}-\frac{13}{2}x+\left(-\frac{13}{4}\right)^{2}=\left(-\frac{13}{4}\right)^{2}$$

Pūruatia -\frac{13}{4} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}-\frac{13}{2}x+\frac{169}{16}=\frac{169}{16}$$

Tauwehea x^{2}-\frac{13}{2}x+\frac{169}{16}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{13}{4}\right)^{2}=\frac{169}{16}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x-\frac{13}{4}\right)^{2}}=\sqrt{\frac{169}{16}}$$

Whakarūnātia.

$$x-\frac{13}{4}=\frac{13}{4} x-\frac{13}{4}=-\frac{13}{4}$$

Me tāpiri \frac{13}{4} ki ngā taha e rua o te whārite.

$$x=\frac{13}{2} x=0$$