Whakaoti i te 2x^2-(3-6a)x-2=0

$$2 x ^ { 2 } - ( 3 - 6 a ) x - 2 = 0$$

Whakaoti mō a

$$a=-\frac{x}{3}+\frac{1}{2}+\frac{1}{3x}$$

$$x\neq 0$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te 3-6a ki te x.

$$2x^{2}-\left(3x-6ax\right)-2=0$$

Hei kimi i te tauaro o 3x-6ax, kimihia te tauaro o ia taurangi.

$$2x^{2}-3x+6ax-2=0$$

Tangohia te 2x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-3x+6ax-2=-2x^{2}$$

Me tāpiri te 3x ki ngā taha e rua.

$$6ax-2=-2x^{2}+3x$$

Me tāpiri te 2 ki ngā taha e rua.

$$6ax=-2x^{2}+3x+2$$

He hanga arowhānui tō te whārite.

$$6xa=2+3x-2x^{2}$$

Whakawehea ngā taha e rua ki te 6x.

$$\frac{6xa}{6x}=\frac{\left(2-x\right)\left(2x+1\right)}{6x}$$

Mā te whakawehe ki te 6x ka wetekia te whakareanga ki te 6x.

$$a=\frac{\left(2-x\right)\left(2x+1\right)}{6x}$$

Whakawehe \left(1+2x\right)\left(2-x\right) ki te 6x.

$$a=-\frac{x}{3}+\frac{1}{2}+\frac{1}{3x}$$

Whakaoti mō x

$$x=\frac{\sqrt{36a^{2}-36a+25}}{4}-\frac{3a}{2}+\frac{3}{4}$$

$$x=-\frac{\sqrt{36a^{2}-36a+25}}{4}-\frac{3a}{2}+\frac{3}{4}$$