Whakaoti i te 2x^2geq8

$$2 x ^ { 2 } \geq 8$$

Whakaoti mō x

$$x\in (-\infty,-2]\cup [2,\infty)$$

Ngā Upane Otinga

Whakawehea ngā taha e rua ki te 2. I te mea he tōrunga te 2, kāore e huri te ahunga koreōrite.

$$x^{2}\geq \frac{8}{2}$$

Whakawehea te 8 ki te 2, kia riro ko 4.

$$x^{2}\geq 4$$

Tātaitia te pūtakerua o 4 kia tae ki 2. Tuhia anō te 4 hei 2^{2}.

$$x^{2}\geq 2^{2}$$

E mau ana te koreōrite mō |x|\geq 2.

$$|x|\geq 2$$

Tuhia anō te |x|\geq 2 hei x\leq -2\text{; }x\geq 2.

$$x\leq -2\text{; }x\geq 2$$