Whakaoti mō y
y=-2x-\frac{16}{x}
x\neq 0
Whakaoti mō x (complex solution)
x=\frac{\sqrt{y^{2}-128}-y}{4}
x=\frac{-\sqrt{y^{2}-128}-y}{4}
Whakaoti mō x
x=\frac{\sqrt{y^{2}-128}-y}{4}
x=\frac{-\sqrt{y^{2}-128}-y}{4}\text{, }|y|\geq 8\sqrt{2}
Graph
Tohaina
Kua tāruatia ki te papatopenga
xy=-16-2x^{2}
Tangohia te 2x^{2} mai i ngā taha e rua.
xy=-2x^{2}-16
He hanga arowhānui tō te whārite.
\frac{xy}{x}=\frac{-2x^{2}-16}{x}
Whakawehea ngā taha e rua ki te x.
y=\frac{-2x^{2}-16}{x}
Mā te whakawehe ki te x ka wetekia te whakareanga ki te x.
y=-2x-\frac{16}{x}
Whakawehe -16-2x^{2} ki te x.
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