Whakaoti i te 2x^2+8x-y+8=0

$$2 x ^ { 2 } + 8 x - y + 8 = 0$$

Whakaoti mō y

$$y=2\left(x+2\right)^{2}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 2x^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$8x-y+8=-2x^{2}$$

Tangohia te 8x mai i ngā taha e rua.

$$-y+8=-2x^{2}-8x$$

Tangohia te 8 mai i ngā taha e rua.

$$-y=-2x^{2}-8x-8$$

Whakawehea ngā taha e rua ki te -1.

$$\frac{-y}{-1}=-\frac{2\left(x+2\right)^{2}}{-1}$$

Mā te whakawehe ki te -1 ka wetekia te whakareanga ki te -1.

$$y=-\frac{2\left(x+2\right)^{2}}{-1}$$

Whakawehe -2\left(2+x\right)^{2} ki te -1.

$$y=2\left(x+2\right)^{2}$$

Whakaoti mō x (complex solution)

$$x=\frac{\sqrt{2y}}{2}-2$$

$$x=-\frac{\sqrt{2y}}{2}-2$$

Whakaoti mō x

$$x=\frac{\sqrt{2y}}{2}-2$$

$$x=-\frac{\sqrt{2y}}{2}-2\text{, }y\geq 0$$