Whakaoti i te 2x^2+3x-20=0

$$2 x ^ { 2 } + 3 x - 20 = 0$$

Whakaoti mō x

$$x=-4$$

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Ngā Upane Whakamahi Tauwehe Mā te Whakarōpū

Hei whakaoti i te whārite, whakatauwehea te taha mauī mā te whakarōpū. Tuatahi, me tuhi anō te taha mauī hei 2x^{2}+ax+bx-20. Hei kimi a me b, whakaritea tētahi pūnaha kia whakaoti.

$$a+b=3 ab=2\left(-20\right)=-40$$

I te mea kua tōraro te ab, he tauaro ngā tohu o a me b. I te mea kua tōrunga te a+b, he nui ake te uara pū o te tau tōrunga i tō te tōraro. Whakarārangitia ngā tau tōpū takirua pērā katoa ka hoatu i te hua -40.

$$-1,40 -2,20 -4,10 -5,8$$

Tātaihia te tapeke mō ia takirua.

$$-1+40=39 -2+20=18 -4+10=6 -5+8=3$$

Ko te otinga te takirua ka hoatu i te tapeke 3.

$$a=-5 b=8$$

Tuhia anō te 2x^{2}+3x-20 hei \left(2x^{2}-5x\right)+\left(8x-20\right).

$$\left(2x^{2}-5x\right)+\left(8x-20\right)$$

Tauwehea te x i te tuatahi me te 4 i te rōpū tuarua.

$$x\left(2x-5\right)+4\left(2x-5\right)$$

Whakatauwehea atu te kīanga pātahi 2x-5 mā te whakamahi i te āhuatanga tātai tohatoha.

$$\left(2x-5\right)\left(x+4\right)$$

Hei kimi otinga whārite, me whakaoti te 2x-5=0 me te x+4=0.

$$x=\frac{5}{2} x=-4$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$2x^{2}+3x-20=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 3 mō b, me -20 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-3±\sqrt{3^{2}-4\times 2\left(-20\right)}}{2\times 2}$$

Pūrua 3.

$$x=\frac{-3±\sqrt{9-4\times 2\left(-20\right)}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{-3±\sqrt{9-8\left(-20\right)}}{2\times 2}$$

Whakareatia -8 ki te -20.

$$x=\frac{-3±\sqrt{9+160}}{2\times 2}$$

Tāpiri 9 ki te 160.

$$x=\frac{-3±\sqrt{169}}{2\times 2}$$

Tuhia te pūtakerua o te 169.

$$x=\frac{-3±13}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{-3±13}{4}$$

Nā, me whakaoti te whārite x=\frac{-3±13}{4} ina he tāpiri te ±. Tāpiri -3 ki te 13.

$$x=\frac{10}{4}$$

Whakahekea te hautanga \frac{10}{4} ki ōna wāhi pāpaku rawa mā te tango me te whakakore i te 2.

$$x=\frac{5}{2}$$

Nā, me whakaoti te whārite x=\frac{-3±13}{4} ina he tango te ±. Tango 13 mai i -3.

$$x=-\frac{16}{4}$$

Whakawehe -16 ki te 4.

$$x=-4$$

Kua oti te whārite te whakatau.

$$x=\frac{5}{2} x=-4$$

Ngā Upane mō te Whakaoti i te Pūrua

Ko ngā whārite pūrua pēnei i tēnei nā ka taea te whakaoti mā te whakaoti i te pūrua. Hei whakaoti i te pūrua, ko te whārite me mātua tuhi ki te āhua x^{2}+bx=c.

$$2x^{2}+3x-20=0$$

Me tāpiri 20 ki ngā taha e rua o te whārite.

$$2x^{2}+3x-20-\left(-20\right)=-\left(-20\right)$$

Mā te tango i te -20 i a ia ake anō ka toe ko te 0.

$$2x^{2}+3x=-\left(-20\right)$$

Tango -20 mai i 0.

$$2x^{2}+3x=20$$

Whakawehea ngā taha e rua ki te 2.

$$\frac{2x^{2}+3x}{2}=\frac{20}{2}$$

Mā te whakawehe ki te 2 ka wetekia te whakareanga ki te 2.

$$x^{2}+\frac{3}{2}x=\frac{20}{2}$$

Whakawehe 20 ki te 2.

$$x^{2}+\frac{3}{2}x=10$$

Whakawehea te \frac{3}{2}, te tau whakarea o te kīanga tau x, ki te 2 kia riro ai te \frac{3}{4}. Nā, tāpiria te pūrua o te \frac{3}{4} ki ngā taha e rua o te whārite. Mā konei e pūrua tika tonu ai te taha mauī o te whārite.

$$x^{2}+\frac{3}{2}x+\left(\frac{3}{4}\right)^{2}=10+\left(\frac{3}{4}\right)^{2}$$

Pūruatia \frac{3}{4} mā te pūrua i te taurunga me te tauraro o te hautanga.

$$x^{2}+\frac{3}{2}x+\frac{9}{16}=10+\frac{9}{16}$$

Tāpiri 10 ki te \frac{9}{16}.

$$x^{2}+\frac{3}{2}x+\frac{9}{16}=\frac{169}{16}$$

Tauwehea x^{2}+\frac{3}{2}x+\frac{9}{16}. Ko te tikanga pūnoa, ina ko x^{2}+bx+c he pūrua tika pūrua tika pū, ka taea taua mea te tauwehea i ngā wā katoa hei \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+\frac{3}{4}\right)^{2}=\frac{169}{16}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$\sqrt{\left(x+\frac{3}{4}\right)^{2}}=\sqrt{\frac{169}{16}}$$

Whakarūnātia.

$$x+\frac{3}{4}=\frac{13}{4} x+\frac{3}{4}=-\frac{13}{4}$$

Me tango \frac{3}{4} mai i ngā taha e rua o te whārite.

$$x=\frac{5}{2} x=-4$$