Whakaoti i te 2x^2+2=5

$$2 x ^ { 2 } + 2 = 5$$

Whakaoti mō x

$$x = \frac{\sqrt{6}}{2} \approx 1.224744871$$

$$x = -\frac{\sqrt{6}}{2} \approx -1.224744871$$

Ngā Upane mā te Kimi Pūtakerua

Tangohia te 2 mai i ngā taha e rua.

$$2x^{2}=5-2$$

Tangohia te 2 i te 5, ka 3.

$$2x^{2}=3$$

Whakawehea ngā taha e rua ki te 2.

$$x^{2}=\frac{3}{2}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=\frac{\sqrt{6}}{2} x=-\frac{\sqrt{6}}{2}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tangohia te 5 mai i ngā taha e rua.

$$2x^{2}+2-5=0$$

Tangohia te 5 i te 2, ka -3.

$$2x^{2}-3=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 0 mō b, me -3 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-3\right)}}{2\times 2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2\left(-3\right)}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8\left(-3\right)}}{2\times 2}$$

Whakareatia -8 ki te -3.

$$x=\frac{0±\sqrt{24}}{2\times 2}$$

Tuhia te pūtakerua o te 24.

$$x=\frac{0±2\sqrt{6}}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{0±2\sqrt{6}}{4}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{6}}{4} ina he tāpiri te ±.

$$x=\frac{\sqrt{6}}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2\sqrt{6}}{4} ina he tango te ±.

$$x=-\frac{\sqrt{6}}{2}$$

Kua oti te whārite te whakatau.

$$x=\frac{\sqrt{6}}{2} x=-\frac{\sqrt{6}}{2}$$