Whakaoti i te 2x^-6(x^-3/x^-10)

$$2 x ^ { - 6 } ( x ^ { - 3 } / x ^ { - 10 } )$$

Aromātai

$$2x$$

Ngā Upane Otinga

Hei whakawehe ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga. Me tango te -10 i te -3 kia riro ai te 7.

$$2x^{-6}x^{7}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -6 me te 7 kia riro ai te 1.

$$2x^{1}$$

Tātaihia te x mā te pū o 1, kia riro ko x.

$$2x$$

Kimi Pārōnaki e ai ki x

$$2$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Hei whakawehe ngā pū o te pūtake kotahi, tangohia te taupū o te tauraro mai i te taupū o te taurunga. Me tango te -10 i te -3 kia riro ai te 7.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{-6}x^{7})$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te -6 me te 7 kia riro ai te 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x^{1})$$

Tātaihia te x mā te pū o 1, kia riro ko x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(2x)$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$2x^{1-1}$$

Tango 1 mai i 1.

$$2x^{0}$$

Mō tētahi kupu t mahue te 0, t^{0}=1.

$$2\times 1$$

Mō tētahi kupu t, t\times 1=t me 1t=t.

$$2$$