Whakaoti i te 2x=x+1/x

$$2 x = x + \frac { 1 } { x }$$

Whakaoti mō x

$$x=-1$$

$$x=1$$

Ngā Upane mā te Kimi Pūtakerua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$2xx=xx+1$$

Whakareatia te x ki te x, ka x^{2}.

$$2x^{2}=xx+1$$

Whakareatia te x ki te x, ka x^{2}.

$$2x^{2}=x^{2}+1$$

Tangohia te x^{2} mai i ngā taha e rua.

$$2x^{2}-x^{2}=1$$

Pahekotia te 2x^{2} me -x^{2}, ka x^{2}.

$$x^{2}=1$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=1 x=-1$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$2xx=xx+1$$

Whakareatia te x ki te x, ka x^{2}.

$$2x^{2}=xx+1$$

Whakareatia te x ki te x, ka x^{2}.

$$2x^{2}=x^{2}+1$$

Tangohia te x^{2} mai i ngā taha e rua.

$$2x^{2}-x^{2}=1$$

Pahekotia te 2x^{2} me -x^{2}, ka x^{2}.

$$x^{2}=1$$

Tangohia te 1 mai i ngā taha e rua.

$$x^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 1 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\left(-1\right)}}{2}$$

Whakareatia -4 ki te -1.

$$x=\frac{0±\sqrt{4}}{2}$$

Tuhia te pūtakerua o te 4.

$$x=\frac{0±2}{2}$$

Nā, me whakaoti te whārite x=\frac{0±2}{2} ina he tāpiri te ±. Whakawehe 2 ki te 2.

$$x=1$$

Nā, me whakaoti te whārite x=\frac{0±2}{2} ina he tango te ±. Whakawehe -2 ki te 2.

$$x=-1$$

Kua oti te whārite te whakatau.

$$x=1 x=-1$$