Whakaoti i te 2x=8/x

$$2 x = \frac { 8 } { x }$$

Whakaoti mō x

$$x=2$$

$$x=-2$$

Ngā Upane mā te Kimi Pūtakerua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$2xx=8$$

Whakareatia te x ki te x, ka x^{2}.

$$2x^{2}=8$$

Whakawehea ngā taha e rua ki te 2.

$$x^{2}=\frac{8}{2}$$

Whakawehea te 8 ki te 2, kia riro ko 4.

$$x^{2}=4$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$x=2 x=-2$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Tē taea kia ōrite te tāupe x ki 0 nā te kore tautuhi i te whakawehenga mā te kore. Whakareatia ngā taha e rua o te whārite ki te x.

$$2xx=8$$

Whakareatia te x ki te x, ka x^{2}.

$$2x^{2}=8$$

Tangohia te 8 mai i ngā taha e rua.

$$2x^{2}-8=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 2 mō a, 0 mō b, me -8 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 2\left(-8\right)}}{2\times 2}$$

Pūrua 0.

$$x=\frac{0±\sqrt{-4\times 2\left(-8\right)}}{2\times 2}$$

Whakareatia -4 ki te 2.

$$x=\frac{0±\sqrt{-8\left(-8\right)}}{2\times 2}$$

Whakareatia -8 ki te -8.

$$x=\frac{0±\sqrt{64}}{2\times 2}$$

Tuhia te pūtakerua o te 64.

$$x=\frac{0±8}{2\times 2}$$

Whakareatia 2 ki te 2.

$$x=\frac{0±8}{4}$$

Nā, me whakaoti te whārite x=\frac{0±8}{4} ina he tāpiri te ±. Whakawehe 8 ki te 4.

$$x=2$$

Nā, me whakaoti te whārite x=\frac{0±8}{4} ina he tango te ±. Whakawehe -8 ki te 4.

$$x=-2$$

Kua oti te whārite te whakatau.

$$x=2 x=-2$$