Whakaoti i te 2p^2-10p

$$2 p ^ { 2 } - 10 p$$

Tauwehe

$$2p\left(p-5\right)$$

Ngā Upane Otinga

Tauwehea te 2.

$$2\left(p^{2}-5p\right)$$

Whakaarohia te p^{2}-5p. Tauwehea te p.

$$p\left(p-5\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$2p\left(p-5\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$2p^{2}-10p=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$p=\frac{-\left(-10\right)±\sqrt{\left(-10\right)^{2}}}{2\times 2}$$

Tuhia te pūtakerua o te \left(-10\right)^{2}.

$$p=\frac{-\left(-10\right)±10}{2\times 2}$$

Ko te tauaro o -10 ko 10.

$$p=\frac{10±10}{2\times 2}$$

Whakareatia 2 ki te 2.

$$p=\frac{10±10}{4}$$

Nā, me whakaoti te whārite p=\frac{10±10}{4} ina he tāpiri te ±. Tāpiri 10 ki te 10.

$$p=\frac{20}{4}$$

Whakawehe 20 ki te 4.

$$p=5$$

Nā, me whakaoti te whārite p=\frac{10±10}{4} ina he tango te ±. Tango 10 mai i 10.

$$p=\frac{0}{4}$$

Whakawehe 0 ki te 4.

$$p=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 5 mō te x_{1} me te 0 mō te x_{2}.

$$2p^{2}-10p=2\left(p-5\right)p$$

Aromātai

$$2p\left(p-5\right)$$