Whakaoti i te 2n^2-2n

$$2 n ^ { 2 } - 2 n$$

Tauwehe

$$2n\left(n-1\right)$$

Ngā Upane Otinga

Tauwehea te 2.

$$2\left(n^{2}-n\right)$$

Whakaarohia te n^{2}-n. Tauwehea te n.

$$n\left(n-1\right)$$

Me tuhi anō te kīanga whakatauwehe katoa.

$$2n\left(n-1\right)$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Ka taea te huamaha pūrua te tauwehe mā te whakamahi i te huringa ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), ina ko x_{1} me x_{2} ngā otinga o te whārite pūrua ax^{2}+bx+c=0.

$$2n^{2}-2n=0$$

Ko ngā whārite katoa o te āhua ax^{2}+bx+c=0 ka taea te whakaoti mā te whakamahi i te tikanga tātai pūrua: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. E rua ngā otinga ka puta i te tikanga tātai pūrua, ko tētahi ina he tāpiri a ±, ā, ko tētahi ina he tango.

$$n=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}}}{2\times 2}$$

Tuhia te pūtakerua o te \left(-2\right)^{2}.

$$n=\frac{-\left(-2\right)±2}{2\times 2}$$

Ko te tauaro o -2 ko 2.

$$n=\frac{2±2}{2\times 2}$$

Whakareatia 2 ki te 2.

$$n=\frac{2±2}{4}$$

Nā, me whakaoti te whārite n=\frac{2±2}{4} ina he tāpiri te ±. Tāpiri 2 ki te 2.

$$n=\frac{4}{4}$$

Whakawehe 4 ki te 4.

$$n=1$$

Nā, me whakaoti te whārite n=\frac{2±2}{4} ina he tango te ±. Tango 2 mai i 2.

$$n=\frac{0}{4}$$

Whakawehe 0 ki te 4.

$$n=0$$

Tauwehea te kīanga taketake mā te whakamahi i te ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Me whakakapi te 1 mō te x_{1} me te 0 mō te x_{2}.

$$2n^{2}-2n=2\left(n-1\right)n$$

Aromātai

$$2n\left(n-1\right)$$