Whakaoti i te 2m^2+6m^2=1

$$2 m ^ { 2 } + 6 m ^ { 2 } = 1$$

Whakaoti mō m

$$m=\frac{\sqrt{2}}{4}\approx 0.353553391$$

$$m=-\frac{\sqrt{2}}{4}\approx -0.353553391$$

Ngā Upane mā te Kimi Pūtakerua

Pahekotia te 2m^{2} me 6m^{2}, ka 8m^{2}.

$$8m^{2}=1$$

Whakawehea ngā taha e rua ki te 8.

$$m^{2}=\frac{1}{8}$$

Tuhia te pūtakerua o ngā taha e rua o te whārite.

$$m=\frac{\sqrt{2}}{4} m=-\frac{\sqrt{2}}{4}$$

Ngā Upane e Whakamahi ana i te Tikanga Tātai Pūrua

Pahekotia te 2m^{2} me 6m^{2}, ka 8m^{2}.

$$8m^{2}=1$$

Tangohia te 1 mai i ngā taha e rua.

$$8m^{2}-1=0$$

Kei te āhua arowhānui tēnei whārite: ax^{2}+bx+c=0. Me whakakapi 8 mō a, 0 mō b, me -1 mō c i te tikanga tātai pūrua, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$m=\frac{0±\sqrt{0^{2}-4\times 8\left(-1\right)}}{2\times 8}$$

Pūrua 0.

$$m=\frac{0±\sqrt{-4\times 8\left(-1\right)}}{2\times 8}$$

Whakareatia -4 ki te 8.

$$m=\frac{0±\sqrt{-32\left(-1\right)}}{2\times 8}$$

Whakareatia -32 ki te -1.

$$m=\frac{0±\sqrt{32}}{2\times 8}$$

Tuhia te pūtakerua o te 32.

$$m=\frac{0±4\sqrt{2}}{2\times 8}$$

Whakareatia 2 ki te 8.

$$m=\frac{0±4\sqrt{2}}{16}$$

Nā, me whakaoti te whārite m=\frac{0±4\sqrt{2}}{16} ina he tāpiri te ±.

$$m=\frac{\sqrt{2}}{4}$$

Nā, me whakaoti te whārite m=\frac{0±4\sqrt{2}}{16} ina he tango te ±.

$$m=-\frac{\sqrt{2}}{4}$$

Kua oti te whārite te whakatau.

$$m=\frac{\sqrt{2}}{4} m=-\frac{\sqrt{2}}{4}$$