Whakaoti i te 2b^3*(b^4)^2=

$$2 b ^ { 3 } \cdot ( b ^ { 4 } ) ^ { 2 } =$$

Aromātai

$$2b^{11}$$

Ngā Upane Otinga

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 4 me te 2 kia riro ai te 8.

$$2b^{3}b^{8}$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 3 me te 8 kia riro ai te 11.

$$2b^{11}$$

Kimi Pārōnaki e ai ki b

$$22b^{10}$$

Ngā Upane e Whakamahi ana i te Tautuhinga o te Pārōnaki

Hei hiki pū ki tētahi pū anō, me whakarea ngā taupū. Me whakarea te 4 me te 2 kia riro ai te 8.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2b^{3}b^{8})$$

Hei whakarea i ngā pū o te pūtake kotahi, me tāpiri ō rātou taupū. Tāpiria te 3 me te 8 kia riro ai te 11.

$$\frac{\mathrm{d}}{\mathrm{d}b}(2b^{11})$$

Ko te pārōnaki o ax^{n} ko nax^{n-1}.

$$11\times 2b^{11-1}$$

Whakareatia 11 ki te 2.

$$22b^{11-1}$$

Tango 1 mai i 11.

$$22b^{10}$$