Whakaoti i te 2a^2-12a+6m=0

$$2 a ^ { 2 } - 12 a + 6 m = 0$$

Whakaoti mō m

$$m=-\frac{a\left(a-6\right)}{3}$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Tangohia te 2a^{2} mai i ngā taha e rua. Ko te tau i tango i te kore ka hua ko tōna korenga.

$$-12a+6m=-2a^{2}$$

Me tāpiri te 12a ki ngā taha e rua.

$$6m=-2a^{2}+12a$$

He hanga arowhānui tō te whārite.

$$6m=12a-2a^{2}$$

Whakawehea ngā taha e rua ki te 6.

$$\frac{6m}{6}=\frac{2a\left(6-a\right)}{6}$$

Mā te whakawehe ki te 6 ka wetekia te whakareanga ki te 6.

$$m=\frac{2a\left(6-a\right)}{6}$$

Whakawehe 2a\left(6-a\right) ki te 6.

$$m=\frac{a\left(6-a\right)}{3}$$

Whakaoti mō a

$$a=\sqrt{9-3m}+3$$

$$a=-\sqrt{9-3m}+3\text{, }m\leq 3$$