Whakaoti i te 2-1/3(m-1)=2

$$2 - \frac { 1 } { 3 } ( m - 1 ) = 2$$

Whakaoti mō m

$$m=1$$

Ngā Upane mō te Whakaoti Whārite Rārangi

Whakamahia te āhuatanga tohatoha hei whakarea te -\frac{1}{3} ki te m-1.

$$2-\frac{1}{3}m-\frac{1}{3}\left(-1\right)=2$$

Whakareatia te -\frac{1}{3} ki te -1, ka \frac{1}{3}.

$$2-\frac{1}{3}m+\frac{1}{3}=2$$

Me tahuri te 2 ki te hautau \frac{6}{3}.

$$\frac{6}{3}-\frac{1}{3}m+\frac{1}{3}=2$$

Tā te mea he rite te tauraro o \frac{6}{3} me \frac{1}{3}, me tāpiri rāua mā te tāpiri i ō raua taurunga.

$$\frac{6+1}{3}-\frac{1}{3}m=2$$

Tāpirihia te 6 ki te 1, ka 7.

$$\frac{7}{3}-\frac{1}{3}m=2$$

Tangohia te \frac{7}{3} mai i ngā taha e rua.

$$-\frac{1}{3}m=2-\frac{7}{3}$$

Me tahuri te 2 ki te hautau \frac{6}{3}.

$$-\frac{1}{3}m=\frac{6}{3}-\frac{7}{3}$$

Tā te mea he rite te tauraro o \frac{6}{3} me \frac{7}{3}, me tango rāua mā te tango i ō raua taurunga.

$$-\frac{1}{3}m=\frac{6-7}{3}$$

Tangohia te 7 i te 6, ka -1.

$$-\frac{1}{3}m=-\frac{1}{3}$$

Me whakarea ngā taha e rua ki te -3, te tau utu o -\frac{1}{3}.

$$m=-\frac{1}{3}\left(-3\right)$$

Tuhia te -\frac{1}{3}\left(-3\right) hei hautanga kotahi.

$$m=\frac{-\left(-3\right)}{3}$$

Whakareatia te -1 ki te -3, ka 3.

$$m=\frac{3}{3}$$

Whakawehea te 3 ki te 3, kia riro ko 1.

$$m=1$$